document.write( "Question 169537: A photo is 3 inches longer that it is wide. A 2-inch border is placed around the photo making the total area of the photo and border 108 square inches. What are the dimensions of the photo? \n" ); document.write( "
Algebra.Com's Answer #125248 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! A photo is 3 inches longer that it is wide. A 2-inch border is placed around the photo making the total area of the photo and border 108 square inches. What are the dimensions of the photo? \n" ); document.write( ". \n" ); document.write( "Let w = width of photo \n" ); document.write( "then \n" ); document.write( "w+3 = length of photo \n" ); document.write( ". \n" ); document.write( "If a 2-inch border is added: \n" ); document.write( "width is: \n" ); document.write( "w+2+2 = w+4 \n" ); document.write( ". \n" ); document.write( "length is: \n" ); document.write( "w+3+2+2 = w+7 \n" ); document.write( ". \n" ); document.write( "(w+4)(w+7) = 108 \n" ); document.write( "w^2 + 7w + 4w + 28 = 108 \n" ); document.write( "w^2 + 11w + 28 = 108 \n" ); document.write( "w^2 + 11w - 80 = 0 \n" ); document.write( ". \n" ); document.write( "Factoring we get: \n" ); document.write( "(w+16)(w-5) = 0 \n" ); document.write( "w = {5, -16} \n" ); document.write( ". \n" ); document.write( "We can toss out the negative solution so we get: \n" ); document.write( "w = 5 inches (width) \n" ); document.write( ". \n" ); document.write( "Length: \n" ); document.write( "w+3 = 8+3 = 11 inches (length) \n" ); document.write( " |