document.write( "Question 169537: A photo is 3 inches longer that it is wide. A 2-inch border is placed around the photo making the total area of the photo and border 108 square inches. What are the dimensions of the photo? \n" ); document.write( "
Algebra.Com's Answer #125248 by nerdybill(7384)\"\" \"About 
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A photo is 3 inches longer that it is wide. A 2-inch border is placed around the photo making the total area of the photo and border 108 square inches. What are the dimensions of the photo?
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\n" ); document.write( "Let w = width of photo
\n" ); document.write( "then
\n" ); document.write( "w+3 = length of photo
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\n" ); document.write( "If a 2-inch border is added:
\n" ); document.write( "width is:
\n" ); document.write( "w+2+2 = w+4
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\n" ); document.write( "length is:
\n" ); document.write( "w+3+2+2 = w+7
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\n" ); document.write( "(w+4)(w+7) = 108
\n" ); document.write( "w^2 + 7w + 4w + 28 = 108
\n" ); document.write( "w^2 + 11w + 28 = 108
\n" ); document.write( "w^2 + 11w - 80 = 0
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\n" ); document.write( "Factoring we get:
\n" ); document.write( "(w+16)(w-5) = 0
\n" ); document.write( "w = {5, -16}
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\n" ); document.write( "We can toss out the negative solution so we get:
\n" ); document.write( "w = 5 inches (width)
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\n" ); document.write( "Length:
\n" ); document.write( "w+3 = 8+3 = 11 inches (length)
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