document.write( "Question 169828: Help please,\r
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document.write( "The speed of the current in a river is 2mph. Jay travels 20 miles upstream and then 20 miles downstream in a total time of hours. Find the speed of the boat.
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document.write( "Let s be the speed of the boat.\r
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document.write( "Thanks \n" );
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Algebra.Com's Answer #125232 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! BELIEVE YOU LEFT OUT THE HOUR FIGURE???? \n" ); document.write( "The speed of the current in a river is 2mph. Jay travels 20 miles upstream and then 20 miles downstream in a total time of 5 1/3 hours. Find the speed of the boat. Let s be the speed of the boat. \n" ); document.write( "D=ST \n" ); document.write( "T=D/S \n" ); document.write( "5.33=20/(S-2)+20/(S+2) \n" ); document.write( "5.33=(20[S+2]+20[S-2])/(S+2)(S-2) \n" ); document.write( "5.33=(20S+40+20S-40)/(S^2-4) \n" ); document.write( "5.33=40S/(S^2-4) \n" ); document.write( "5.33S^2-21.333=40S \n" ); document.write( "5.33S^2-40S-21.333=0 \n" ); document.write( "uSING THE QUADRATIC EQUATION \n" ); document.write( "S=(40+-SQRT[-40^2-4*5.33*-21.333])/2*5.333 \n" ); document.write( "S=(40+-SQRT[1,600+455])/10.6667 \n" ); document.write( "S=(40+-SQRT2,055)/10.6667 \n" ); document.write( "S=(40+-SQRT45.333)/10.667 \n" ); document.write( "S=(40+45.333)/10.667 \n" ); document.write( "S=85.333/10.667 \n" ); document.write( "S=8 MPH. ANS FOR THE SPEED OF THE BOAT IN CALM WATERS. \n" ); document.write( " |