document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169816>Question 169816</A>: <I><SPAN STYLE=\"word-break: break-all;\">      <BR>\n" );
document.write( "Determine if given function is one to one.  If it is, find the formula for the inverse.\r<BR>\n" );
document.write( "\n" );
document.write( "f(x)=5x-6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #125212 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=125212\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Determine if given function is one to one. If it is, find the formula for the inverse. <BR>\n" );
document.write( "f(x)=5x-6<BR>\n" );
document.write( "It is one-to-one because each x-value has one corresponding y-value and<BR>\n" );
document.write( "vice versa.<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "Inverse:<BR>\n" );
document.write( "Interchange x and y to get:<BR>\n" );
document.write( "x = 5y-6<BR>\n" );
document.write( "Solve for \"Y\" to get the inverse:<BR>\n" );
document.write( "y = (1/5)x + (6/5)<BR>\n" );
document.write( "==================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );