document.write( "Question 169783: Find the hypotenuse of a right triangle with sides 5 inches and 10 inches. \n" ); document.write( "
Algebra.Com's Answer #125166 by jim_thompson5910(35256)\"\" \"About 
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We basically have this triangle set up:\r
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\n" ); document.write( "\n" ); document.write( "Since we can see that the triangle has legs of 5 and 10 with a hypotenuse of x, we can use Pythagoreans theorem to find the unknown side.\r
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\n" ); document.write( "\n" ); document.write( "Pythagoreans theorem:\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2%2Bb%5E2=c%5E2\" where a and b are the legs of the triangle and c is the hypotenuse\r
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\n" ); document.write( "\n" ); document.write( "\"5%5E2%2B10%5E2=x%5E2\" Plug in a=5, b=10, and c=x. Now lets solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"2+5+%2B+1+0+0+=++x++%5E+2\" Square each individual term\r
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\n" ); document.write( "\n" ); document.write( "\"1+2+5+=++x++%5E+2\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"s+q+r+t+%28+1+2+5+%29+=+s+q+r+t+%28++x++%5E+2+%29\" Take the square root of both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x=5%2Asqrt%285%29\" Simplify the square root. Note: only the positive square root is considered\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"x=5%2Asqrt%285%29\"\r
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\n" ); document.write( "\n" ); document.write( "Which approximates to \"x=11.18034\"\r
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\n" ); document.write( "\n" ); document.write( "So the hypotenuse is approximately 11.18034 inches
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