document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169771>Question 169771</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the equation of the line passing through (3,-2), but perpendicular to y=3.\r<BR>\n" );
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document.write( "I tried to use the point-slope intercept form to find the slope, but I do not have two points given. So I used the first point (3,-2) and (0,3) since y=3. Then I tried to find my slope.\r<BR>\n" );
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document.write( "y2-y1/x2-x1= 3-(-2)/0-3= -5/3 <BR>\n" );
document.write( "now I have a slope of -5/3\r<BR>\n" );
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document.write( "Next I tried to use the point-slope equation\r<BR>\n" );
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document.write( "y-y1=m(x-x1)<BR>\n" );
document.write( "y-(-2)=-5/3(x-3)<BR>\n" );
document.write( "y+2=-5/3(x-3)<BR>\n" );
document.write( "3y+6=-3x+9<BR>\n" );
document.write( "3y=-3x+3<BR>\n" );
document.write( "Y=-x+1 \r<BR>\n" );
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document.write( "Now that I have my equation is this equation perpendicular to y=3? <BR>\n" );
document.write( "Do I have the right concept? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #125149 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=125149\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You made this way too difficult on yourself.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=3 ALIGN=MIDDLE  ALT=\"y=3\"   DISABLED_style= \"max-width:90%; height:auto;\" > is a horizontal line, therefore the desired perpendicular must be a vertical line.  Vertical lines have the characteristic that the x-coordinate for any ordered pair representing a point on the line is a constant value, and the y-coordinate can be any real number.  Hence, if the desired line passes through (3,-2), then the x-coordinate of ALL points on the line must be 3 and therefore the equation of the desired line is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=3 ALIGN=MIDDLE  ALT=\"x=3\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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