document.write( "Question 169761: I am having a porblem trying to figure out how to work this problem please help..\r
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document.write( "solve each equation and please show your work\r
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document.write( "sqrt of 2w^2 -3w - 4 = sqrt w^2+ 6w + 6\r
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document.write( "I know that you have to get the problem on one side to + 0, but I am having problems with trying to work it out, please help me. Thank you \n" );
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Algebra.Com's Answer #125121 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! sqrt(2w^2-3w-4)=sqrt(w^2+6w+6) \n" ); document.write( "squaring both sides we get: \n" ); document.write( "2w^2-3w-4=w^2+6w+6 \n" ); document.write( "2w^2-w^2-3w-6w-4-6=0 \n" ); document.write( "w^2-9w-10=0 \n" ); document.write( "(w-10)(w+1)=0 \n" ); document.write( "w-10=0 \n" ); document.write( "w=10 ans. \n" ); document.write( "w+1=0 \n" ); document.write( "w=-1 ans. \n" ); document.write( "Proof: \n" ); document.write( "sqrt(2*10^2-3*10-4)=sqrt(10^2+6*10+6) \n" ); document.write( "sqrt(2*100-30-4)=sqrt(100+60+6) \n" ); document.write( "sqrt(200-34)=sqrt(166) \n" ); document.write( "sqrt(166)=sqrt(166)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |