document.write( "Question 169688: 1.find four consecutive integers such that twice the smallest is 12 more than the largest
\n" ); document.write( "2.find three consecutive integers such that the sum of the first two integers is 24 more than the third integer.
\n" ); document.write( "3.find three consecutive odd integers such that the sum of the first and the second is 27 less than 3 times the third
\n" ); document.write( "4.find three consecutive even integers such that the sum of the smallest and twice the second is 20 more than the third
\n" ); document.write( "

Algebra.Com's Answer #125085 by Mathtut(3670)\"\" \"About 
You can put this solution on YOUR website!
I will show you 2 problems 1 and 4 and then you should get the pattern of how its done, remembering that consecutive intergers with a given variable a is a,a+1,a+2 etc., whereas consecutive odd or even intergers would be written as a,a+2,a+4 etc. with that background.\r
\n" ); document.write( "\n" ); document.write( "1.) lets call our 4 consecutive integers a,a+1,a+2,a+3
\n" ); document.write( ":
\n" ); document.write( "2 times the smallest which is a=2a....12 more than largest(a+3) is (a+3)+12
\n" ); document.write( ":
\n" ); document.write( "2a=(a+3)+12 subtract a from each side
\n" ); document.write( "\"highlight%28a=15%29\" so our integers are 15,16,17,18
\n" ); document.write( ":
\n" ); document.write( "4.) Lets call our 3 consecutive even integers a, a+2,a+4
\n" ); document.write( "sum of the smallest(a) plus twice the second(2(a+2)) equals 20 more than the 3rd((a+4)+20)
\n" ); document.write( ":
\n" ); document.write( "2a+2(a+2)=(a+4)+20
\n" ); document.write( "3a+4=a+24---->subtract a and -4 from both sides
\n" ); document.write( "2a=20
\n" ); document.write( "\"highlight%28a=10%29\" so our even integers are 10,12,14\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );