document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169691>Question 169691</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the minimum or maximum value of the quadratic function g(x)=2x^2+6x+3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #125071 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=125071\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the minimum (or maximum) lies on the axis of symmetry\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "the general eqn for the axis is x=-b/(2a)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "in this case, x=-6/(2*2) __ x=-3/2\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "so the MINIMUM value (because a is positive) is 2(-3/2)^2+6(-3/2)+3 or -3/2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );