document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169685>Question 169685</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321233832/algebrahomeworkh>elementary and Intermediate algebra concepts and application</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> elementary and Intermediate algebra concepts and application  Please Please Help!!!\r<BR>\n" );
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document.write( "This book is so hard tounderstand .\r<BR>\n" );
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document.write( "Find P(-1/2) if <BR>\n" );
document.write( "     P(x) = 2x^4+x^3+12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #125067 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=125067\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find P(-1/2) if <BR>\n" );
document.write( "P(x) = 2x^4+x^3+12<BR>\n" );
document.write( "P(-1/2) = 2(-1/2)^4 + (-1/2)^3 + 12<BR>\n" );
document.write( "P(-1/2) = 2(1/16) - (1/8) + 12<BR>\n" );
document.write( "P(-1/2) = (1/8) - (1/8) + 12<BR>\n" );
document.write( "P(-1/2) = 12<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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