document.write( "Question 169666: Please simplify the following problem:\r
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document.write( "(1/2)-(1/3)/(3/4)+(1/6) \n" );
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Algebra.Com's Answer #125046 by checkley77(12844) ![]() You can put this solution on YOUR website! (1/2)-(1/3)/(3/4)+(1/6) \n" ); document.write( "1/2-(1/3)(4/3)+1/6 \n" ); document.write( "1/2-4/9+1/6 \n" ); document.write( "-------------------------- \n" ); document.write( "Checkley77, I really appreciate your help on this complex fractions. \n" ); document.write( "Could you eplain how you got step 4- which is (9-4*2-3)/18. I got lost on this step.I really appreciate your help. \n" ); document.write( "--------------------------------------------- \n" ); document.write( "In order to add fractions you need to have a common denominator. \n" ); document.write( "The common denominator is any number evenly divisable by 2, 9 & 6. \n" ); document.write( "A good way to do this is to see if the largest number is divisable by the other two. 9 is not divisable by 2 \n" ); document.write( "Next multiply the largest number (9) by (2)=18 and try again. \n" ); document.write( "18 is divisable by both 2 & 6. \n" ); document.write( "Now you need to change 1/2 to 9/18 by multiplying both numerator & denominator by 9, change 4/9 to 8/18 by multiplying both numerator & denominator by 2 & 1/6 to 3/18 by multiplying both numerator & denominator by 3. \n" ); document.write( "Now you have a 'common denominator' and can add the numerators. \n" ); document.write( "----------------------------------------- \n" ); document.write( "(9*1-4*2+3*1)/18 multiply numerator terms. \n" ); document.write( "(9-8+3)/18 combine numerator terms. \n" ); document.write( "4/18 now reduce. \n" ); document.write( "2/9 ans. \n" ); document.write( " |