document.write( "Question 169662: having trouble solvin this probolem using addition method,substitution and graphing not sure ifm i am suppose to have the same answer for all three methods\r
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document.write( "3x+2y=22
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document.write( "5x-4y=0 \n" );
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Algebra.Com's Answer #125038 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 3x+2y=22 \n" ); document.write( "5x-4y=0 \n" ); document.write( "------------- \n" ); document.write( "Elimination: \n" ); document.write( "6x+4y = 44 \n" ); document.write( "5x-4y = 0 \n" ); document.write( "-------------- \n" ); document.write( "11x = 44 \n" ); document.write( "x = 4 \n" ); document.write( "--- \n" ); document.write( "3*4+2y = 22 \n" ); document.write( "2y = 10 \n" ); document.write( "y = 5 \n" ); document.write( "Ans: (4,5) \n" ); document.write( "=========================== \n" ); document.write( "Substitution: \n" ); document.write( "3x+2y=22 \n" ); document.write( "5x-4y=0 \n" ); document.write( "--------- \n" ); document.write( "x = (4/5)y \n" ); document.write( "3(4/5)y + 2y = 22 \n" ); document.write( "(12/5+ 10/5)y = 22 \n" ); document.write( "(22/5)y = 22 \n" ); document.write( "(1/5)y = 1 \n" ); document.write( "y = 5 \n" ); document.write( "--- \n" ); document.write( "x = (4/5)5 = 4 \n" ); document.write( "Ans: (4,5) \n" ); document.write( "=========================== \n" ); document.write( "Graphing: \n" ); document.write( "3x+2y=22 \n" ); document.write( "5x-4y=0 \n" ); document.write( "------------ \n" ); document.write( "y= (-3/2)x + 11 \n" ); document.write( "y = (5/4)x \n" ); document.write( " \n" ); document.write( "==================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |