document.write( "Question 169645: what is an equation for the line perpendicular to the equation x+2y=8 going through the point (4,0) \n" ); document.write( "
Algebra.Com's Answer #125019 by jojo14344(1513)\"\" \"About 
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what is an equation for the line perpendicular to the equation x+2y=8 going through the point (4,0)
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\n" ); document.write( "We'll see 1st line \"x%2B2y=8\": \"slope=m%5B1%5D=-1%2F2\"
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\n" ); document.write( "Now the line perpendicular has a \"slope=m%5B2%5D=-1%2Fm%5B1%5D\"
\n" ); document.write( "\"m%5B2%5D=-1%2F%28-1%2F2%29=2\"
\n" ); document.write( "Thru points (4,0) via Slope Intercept form:\"y=mx%2Bb\"
\n" ); document.write( "\"0=2%284%29%2Bb\"
\n" ); document.write( "\"b=-8\", y-intercept
\n" ); document.write( "So the line eqn is: \"highlight%28y=2x-8%29\", Answer (Green Line)
\n" ); document.write( "As we see below,
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\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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