document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169645>Question 169645</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is an equation for the line perpendicular to the equation x+2y=8 going through the point (4,0) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #125017 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=125017\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> what is an equation for the line perpendicular to the equation x+2y=8 going through the point (4,0)<BR>\n" );
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document.write( "Find the slope, m, of the line by putting it in the slope-intercept form, y = mx+b.<BR>\n" );
document.write( "x+2y=8<BR>\n" );
document.write( "2y = -x+8<BR>\n" );
document.write( "y = (-1/2)x + 4 so the slope is -1/2<BR>\n" );
document.write( "Then, y-y1 = m*(x-x1) where (x1,y1) is the point (4,0)<BR>\n" );
document.write( "y-0 = (-1/2)*(x-4)<BR>\n" );
document.write( "y = (-1/2)x + 2  slope-int form<BR>\n" );
document.write( "x + 2y = 4  standard form<BR>\n" );
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