document.write( "Question 169615This question is from textbook Discovering Geometry
\n" ); document.write( ": Is the equation 6x-3=39 7?\r
\n" ); document.write( "\n" ); document.write( "how do you do 3y-7=5y+1?\r
\n" ); document.write( "\n" ); document.write( "how do yo do 6x-4(3x+8)=16?
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Algebra.Com's Answer #125000 by Mathtut(3670)\"\" \"About 
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yes, 6x-3=39......x=7 because when you add 3 to each side you have 6x=42
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\n" ); document.write( "then divide by 6 and \"highlight%28x=7%29\"
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\n" ); document.write( "3y-7=5y+1.....subtract 3y and 1 from each side ..which gives you 2y=-8...now
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\n" ); document.write( "divide by 2 and \"highlight%28y=-4%29\"
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\n" ); document.write( "6x-4(3x+8)=16......first distribute the term 4(3x+8)....6x-12x-32=16....now
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\n" ); document.write( "combine the x terms -6x-32=16....add 32 to each side -6x=48....divide by -6....
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\n" ); document.write( "\"highlight%28x=-8%29\"
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