document.write( "Question 169541: A car travels 180mi, a second car, traveling 15mi/h faster than the first car , makes the trip in 1 hr less time. Find the speed of each car. \n" ); document.write( "
Algebra.Com's Answer #124999 by Mathtut(3670)\"\" \"About 
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distance = rate multiplied by time. let r and t be rate and time of 1st car
\n" ); document.write( "and r+15 and t-1 be rate and time of 2nd car.
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\n" ); document.write( "180=rt----------->t=180/r....eq 1
\n" ); document.write( "180=(r+15)(t-1)...eq 2
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\n" ); document.write( "take t's value from eq 1 and substitute it into eq 2
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\n" ); document.write( "\"180=%28r%2B15%29%28%28180%2Fr%29-1%29\"
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\n" ); document.write( "\"180=%28r%2B15%29%28%28180-r%29%2Fr%29\"....multiply by r
\n" ); document.write( "\"180r=%28r%2B15%29%28180-r%29\"....distribute right side
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\n" ); document.write( "\"180r=180r-r%5E2%2B2700-15r\"
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\n" ); document.write( "\"r%5E2%2B15r-2700=0\" use quadratic formula
\n" ); document.write( "\"highlight%28r=45%29\" \"highlight%28r=-60%29\" throw out negative value
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\n" ); document.write( "\"highlight%28r=45%29\" rate of 1st car
\n" ); document.write( "\"highlight%28r%2B15=60%29\" rate of 2nd car:\r
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ar%5E2%2Bbr%2Bc=0\" (in our case \"1r%5E2%2B15r%2B-2700+=+0\") has the following solutons:
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\n" ); document.write( " \"r%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2815%29%5E2-4%2A1%2A-2700=11025\".
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\n" ); document.write( " Discriminant d=11025 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-15%2B-sqrt%28+11025+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"r%5B1%5D+=+%28-%2815%29%2Bsqrt%28+11025+%29%29%2F2%5C1+=+45\"
\n" ); document.write( " \"r%5B2%5D+=+%28-%2815%29-sqrt%28+11025+%29%29%2F2%5C1+=+-60\"
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\n" ); document.write( " Quadratic expression \"1r%5E2%2B15r%2B-2700\" can be factored:
\n" ); document.write( " \"1r%5E2%2B15r%2B-2700+=+1%28r-45%29%2A%28r--60%29\"
\n" ); document.write( " Again, the answer is: 45, -60.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B15%2Ax%2B-2700+%29\"

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