document.write( "Question 169541: A car travels 180mi, a second car, traveling 15mi/h faster than the first car , makes the trip in 1 hr less time. Find the speed of each car. \n" ); document.write( "
Algebra.Com's Answer #124999 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! distance = rate multiplied by time. let r and t be rate and time of 1st car \n" ); document.write( "and r+15 and t-1 be rate and time of 2nd car. \n" ); document.write( ": \n" ); document.write( "180=rt----------->t=180/r....eq 1 \n" ); document.write( "180=(r+15)(t-1)...eq 2 \n" ); document.write( ": \n" ); document.write( "take t's value from eq 1 and substitute it into eq 2 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
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