document.write( "Question 169575This question is from textbook Introductory Algebra
\n" ); document.write( ": A student walks and jogs to college each day. She averages 5 km/h walking and 9 km/h jogging. The distance from home to college is 8 km, and she makes the trip in 1 hr. How far does the student jog? \n" ); document.write( "
Algebra.Com's Answer #124994 by gonzo(654)\"\" \"About 
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let W = rate of walking = 5 km/h
\n" ); document.write( "let J = rate of jogging = 9 km/h
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\n" ); document.write( "D = 8 km (given)
\n" ); document.write( "T = 1 hour (given)
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\n" ); document.write( "rate * time = distance.
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\n" ); document.write( "let x = amount of time walking.
\n" ); document.write( "let y = amount of time jogging.
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\n" ); document.write( "x * W = distance walking.
\n" ); document.write( "y * J = distance jogging.
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\n" ); document.write( "since total time = 1 hour, then x + y = 1
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\n" ); document.write( "since total distance = 8 km, then x*W + y*J = 8
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\n" ); document.write( "you have 2 equations:
\n" ); document.write( "x + y = 1
\n" ); document.write( "x * W + y * J = 8
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\n" ); document.write( "since W = 5 km/h and J = 9 km/h, then second equation becomes:
\n" ); document.write( "x * 5 + y * 9 = 8
\n" ); document.write( "which is the same as
\n" ); document.write( "5x + 9y = 8
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\n" ); document.write( "two equations become:
\n" ); document.write( "x + y = 1
\n" ); document.write( "5x + 9y = 8
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\n" ); document.write( "if x + y = 1, then y = 1 - x
\n" ); document.write( "second equation of 5x + 9y = 8 becomes:
\n" ); document.write( "5x + 9*(1-x) = 8
\n" ); document.write( "remove parentheses:
\n" ); document.write( "5x + 9 - 9x = 8
\n" ); document.write( "combine like terms:
\n" ); document.write( "-4x + 9 = 8
\n" ); document.write( "subtract 9 from both sides:
\n" ); document.write( "-4x = -1
\n" ); document.write( "divide both sides by 4:
\n" ); document.write( "x = 1/4
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\n" ); document.write( "if x = 1/4 and x + y = 1, then y = 3/4
\n" ); document.write( "you have:
\n" ); document.write( "x = 1/4 of an hour.
\n" ); document.write( "y = 3/4 of an hour.
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\n" ); document.write( "you can now solve for distance since you have the rate and the time.
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\n" ); document.write( "equation to use is:
\n" ); document.write( "5x + 9y = 8
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\n" ); document.write( "5*x = 5 * 1/4 = 5/4 miles.
\n" ); document.write( "9*y = 9 * 3/4 = 27/4 miles.
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\n" ); document.write( "she walked 5/4 miles.
\n" ); document.write( "she jogged 27/4 miles.
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\n" ); document.write( "how does this work out?
\n" ); document.write( "in the formula 5x + 9y = 8, we can substitute 1/4 for x since she walked 1 quarter of an hour, and we can susbtitute 3/4 for y since she jogged 3/4 of an hour.
\n" ); document.write( "1/4 * 5 + 3/4 * 9 must equal 8
\n" ); document.write( "5/4 + 27/4 = 32/4 = 8.
\n" ); document.write( "since 8 = 8 the equation is true.
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\n" ); document.write( "student jogged 27/4 miles = 6.75 miles.
\n" ); document.write( "she walked 5/4 miles = 1.25 miles.
\n" ); document.write( "she jogged for 3/4 of an hour.
\n" ); document.write( "she walked for 1/4 of an hour.
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