document.write( "Question 169574This question is from textbook Introductory Algebra
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document.write( ": An employer has a daily payroll of $1225 when employing some workers at $80 per day and others at $85 per day. When the number of $80 workers is increased by 50% and the number of $85 workers is decreased by one-fifth, the new daily payroll is $1540. How many were originally employed at each rate? \n" );
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Algebra.Com's Answer #124992 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! lets call x and y the number of workers paid 80 and 85 dollars respecitively \n" ); document.write( ": \n" ); document.write( "80x+85y=1225...eq 1 \n" ); document.write( ": \n" ); document.write( "80(x=.5x)+85(y-1/5y)=1540----> \n" ); document.write( "120x+68y=1540....eq 2 \n" ); document.write( ": \n" ); document.write( "multiply eq 1 by 3 and eq 2 by -2 to eliminate the x terms \n" ); document.write( ": \n" ); document.write( "255y=3675 \n" ); document.write( "-136y=-3080 \n" ); document.write( "_____________ \n" ); document.write( "119y=595 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "plug y's value into eq 1 or 2...I chose eq 1 \n" ); document.write( ": \n" ); document.write( "80x+85(5)=1540 \n" ); document.write( "80x=800 \n" ); document.write( ": \n" ); document.write( " |