document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169599>Question 169599</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Normal sea water is about 3.5% solids. This is about the same as saying \"There are nearly 300 pounds of dissolved solid matter per thousand gallons of sea water\" Using this information, find the weight of a gallon of sea water. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #124986 by </B><A HREF=/tutors/aboutme.mpl?userid=gonzo><B>gonzo(654)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gonzo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=124986\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 300 pounds of dissolved solids in 1000 gallons of sea water (given).<BR>\n" );
document.write( "normal sea water contains about 3.5% solids (given).<BR>\n" );
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document.write( "based on these facts, you can derive the approximate weight of sea water as follows:<BR>\n" );
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document.write( "there are 300 pounds of solids in 1000 gallons of sea water.<BR>\n" );
document.write( "this represent 3.5% of the total number of gallons of sea water.<BR>\n" );
document.write( "300 pounds of solids is equivalent to 35 gallons of sea water.<BR>\n" );
document.write( "this means that 35 gallons of sea water weighs 300 pounds.<BR>\n" );
document.write( "300 pounds / 35 gallons = 8.571428571 pounds per gallon of sea water.<BR>\n" );
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document.write( "the implicit assumption is that the solids are dissolved throughout the sea water so that the density of the sea water and the solids is the same throughout.<BR>\n" );
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document.write( "i did a check on the web and found that the average weight of a gallon of sea water is in the neighborhood of this answer so i'm confident it's probably right.<BR>\n" );
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document.write( "another way of looking at it would be:<BR>\n" );
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document.write( "300 pounds of solids in 1000 gallons of sea water = .3 pounds of solids in 1 gallon of sea water.<BR>\n" );
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document.write( "since solids are 3.5% of a gallon of sea water, then .3 pounds of solids represents 3.5% of the gallon.<BR>\n" );
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document.write( ".3 pounds / .035 = 8.571428571 pounds for the full gallon.<BR>\n" );
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document.write( "the assumption is again that the solids are diffused through the liquid so that the density of the solids and the liquids is the same throughout.<BR>\n" );
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document.write( "best i can do.<BR>\n" );
document.write( "not sure if i explained it well, but i think the answer is right.\r<BR>\n" );
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