document.write( "Question 169573This question is from textbook Introductory Algebra
\n" ); document.write( ": A goldsmith has two alloys that are different purities of gold. The first is three-fourths pure gold and the second is five-twelfths pure gold. How many ounces of each should be melted and mixed in order to obtain a 6-oz mixture that is two-thirds pure gold? \n" ); document.write( "
Algebra.Com's Answer #124981 by Mathtut(3670)\"\" \"About 
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lets call the 3/4 gold alloy x and the 7/12 alloy y
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\n" ); document.write( "x+y=6....eq 1
\n" ); document.write( ".75x+(7/12)y=2/3(6)...eq 2\r
\n" ); document.write( "\n" ); document.write( "x=6-y from eq 1 and plug it into eq 2
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\n" ); document.write( ".75(6-y)+.4166y=4
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\n" ); document.write( "4.5-.75y+.4166y=4
\n" ); document.write( ":
\n" ); document.write( ".3334y=.5
\n" ); document.write( ":
\n" ); document.write( "\"highlight%28y=1.5%29\" oz of 7/12's alloy
\n" ); document.write( "\"highlight%28x=6-1.5=4.5%29\"oz of 3/4's alloy
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