document.write( "Question 169605: The sum of 3 numbers is 137. The 2nd number is 4 more than twice the first number and the 3rd number is 5 less than 3 times the first. What are the numbers? And what is the formula for finding the numbers please? \n" ); document.write( "
Algebra.Com's Answer #124969 by Mathtut(3670)\"\" \"About 
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lets call the 3 numbers a,b,and c
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\n" ); document.write( "a+b+c=137.....eq 1
\n" ); document.write( "b=2a+4........eq 2
\n" ); document.write( "c=3a-5........eq 3\r
\n" ); document.write( "\n" ); document.write( "take b value from eq 2 and c value from eq 3 and plug them into eq 1
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\n" ); document.write( "a+(2a+4)+(3a-5)=137
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\n" ); document.write( "6a-1=137
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\n" ); document.write( "6a=138
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\n" ); document.write( "\"highlight%28a=23%29\"
\n" ); document.write( "\"highlight%28b=2%2823%29%2B4=50%29\"
\n" ); document.write( "\"highlight%28c=3%2823%29-5=64%29\"
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