document.write( "Question 169605: The sum of 3 numbers is 137. The 2nd number is 4 more than twice the first number and the 3rd number is 5 less than 3 times the first. What are the numbers? And what is the formula for finding the numbers please? \n" ); document.write( "
Algebra.Com's Answer #124969 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! lets call the 3 numbers a,b,and c \n" ); document.write( ": \n" ); document.write( "a+b+c=137.....eq 1 \n" ); document.write( "b=2a+4........eq 2 \n" ); document.write( "c=3a-5........eq 3\r \n" ); document.write( "\n" ); document.write( "take b value from eq 2 and c value from eq 3 and plug them into eq 1 \n" ); document.write( ": \n" ); document.write( "a+(2a+4)+(3a-5)=137 \n" ); document.write( ": \n" ); document.write( "6a-1=137 \n" ); document.write( ": \n" ); document.write( "6a=138 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |