document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169550>Question 169550</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sqrt56+ sqrt126 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #124957 by </B><A HREF=/tutors/aboutme.mpl?userid=midwood_trail><B>midwood_trail(310)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=midwood_trail><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=124957\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sqrt{56} + sqrt{126} =\r<BR>\n" );
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document.write( "Break each sqrt separately.\r<BR>\n" );
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document.write( "sqrt{56} = sqrt{4} times sqrt{14}, where the square root of 4 is a perfect square.\r<BR>\n" );
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document.write( "sqrt{56} = 2(sqrt{14}).\r<BR>\n" );
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document.write( "sqrt{126} = sqrt{9} times sqrt{14}), where sqrt{9} is a perfect square.\r<BR>\n" );
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document.write( "sqrt{126} = 3(sqrt{14})\r<BR>\n" );
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document.write( "Now that we have the same radicand 14, we can add the radicals.\r<BR>\n" );
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document.write( "2(sqrt{14}) + 3(sqrt{14}) = 5(sqrt{14}) as the final answer.\r<BR>\n" );
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document.write( "NOTE: We cannot break down sqrt{14} anymore because it is already in lowest terms.\r<BR>\n" );
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