document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169415>Question 169415</A>: <I><SPAN STYLE=\"word-break: break-all;\"> explain how to solve this for my test!!!<BR>\n" );
document.write( "2- 2/3x > 6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #124916 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=124916\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2-2/3x>6--------> first isolate x on the left so subtract 2 from both sides<BR>\n" );
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document.write( "-2/3x>4--------> to further isolate x you must multiply both sides by -3/2 remembering that when you multiply or divide by a negative number the inequality sign reverses.\r<BR>\n" );
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document.write( "(-3/2)(-2/3)x>4(-3/2)<BR>\n" );
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document.write( "x<-6 </SPAN>\n" );
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