document.write( "Question 169422This question is from textbook Prentice Hall Mathematics Texas Algebra 2
\n" ); document.write( ": The table shows the percent of U.S. houses with cable TV.\r
\n" ); document.write( "\n" ); document.write( "a. Find a quadratic model using 1960 as year 0, 1970 as year 10, and so on.\r
\n" ); document.write( "\n" ); document.write( "b. Use the model to estimate the percent of households with one cable TV in 1995.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Years-%of household
\n" ); document.write( "1960-0
\n" ); document.write( "1970-7
\n" ); document.write( "1980-20
\n" ); document.write( "1990-56
\n" ); document.write( "2000-68
\n" ); document.write( "

Algebra.Com's Answer #124914 by checkley77(12844)\"\" \"About 
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(2000-1990)/(68-56)
\n" ); document.write( "10/12=.8333 per year between 1990 & 2000
\n" ); document.write( "1990+5yrs=56+5*.8333
\n" ); document.write( "5*.8333=4.1667
\n" ); document.write( "56+4.1667=60.1667 answer for the number of households with cable TV in 1995.
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