document.write( "Question 169320This question is from textbook Introductory Algebra
\n" ); document.write( ": Solve the problem. A man rode a bicycle for 12 miles and then hiked an additional 8 miles. The total time for the trip was 5 hours. If his rate when he was riding a bicycle was 10 miles per hour faster than his rate walking, what was each rate? \n" ); document.write( "
Algebra.Com's Answer #124900 by checkley77(12844)\"\" \"About 
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D=RT OR D/R=T
\n" ); document.write( "12/X+8/(X-10)=5
\n" ); document.write( "[12(X-10)+8X]/X(X-10)=5
\n" ); document.write( "[12X-120+8X]/(X^2-10X)=5
\n" ); document.write( "20X-120=5X^2-50X
\n" ); document.write( "5X^2-50X-20X+120=0
\n" ); document.write( "5X^2-70X+120=0
\n" ); document.write( "5(X^2-14X+24)=0
\n" ); document.write( "5(X-12)(X-2)=0
\n" ); document.write( "X-12=0
\n" ); document.write( "X=12 ANS. FOR THE BIKE SPEED.
\n" ); document.write( "12-10=2 ANS. FOR THE WALKING SPEED.
\n" ); document.write( "PROOF:
\n" ); document.write( "12/12+8/2=5
\n" ); document.write( "1+4=5
\n" ); document.write( "5=5\r
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