document.write( "Question 169320This question is from textbook Introductory Algebra
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document.write( ": Solve the problem. A man rode a bicycle for 12 miles and then hiked an additional 8 miles. The total time for the trip was 5 hours. If his rate when he was riding a bicycle was 10 miles per hour faster than his rate walking, what was each rate? \n" );
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Algebra.Com's Answer #124900 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT OR D/R=T \n" ); document.write( "12/X+8/(X-10)=5 \n" ); document.write( "[12(X-10)+8X]/X(X-10)=5 \n" ); document.write( "[12X-120+8X]/(X^2-10X)=5 \n" ); document.write( "20X-120=5X^2-50X \n" ); document.write( "5X^2-50X-20X+120=0 \n" ); document.write( "5X^2-70X+120=0 \n" ); document.write( "5(X^2-14X+24)=0 \n" ); document.write( "5(X-12)(X-2)=0 \n" ); document.write( "X-12=0 \n" ); document.write( "X=12 ANS. FOR THE BIKE SPEED. \n" ); document.write( "12-10=2 ANS. FOR THE WALKING SPEED. \n" ); document.write( "PROOF: \n" ); document.write( "12/12+8/2=5 \n" ); document.write( "1+4=5 \n" ); document.write( "5=5\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |