document.write( "Question 169397: The volume of a gas is inversely proportional to the pressure on the gas. If the volume is 6 cubic centimeters when the pressure on the gas is 8 kilograms per square centimeter, then what is the volume when the pressure is 12 kilograms per square centimeters.\r
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document.write( "Help, thank you \n" );
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Algebra.Com's Answer #124895 by gonzo(654)![]() ![]() ![]() You can put this solution on YOUR website! direct proportion would be x = k*y \n" ); document.write( "inverse proportion would be x = k/y \n" ); document.write( "where k is a constant of proportionality. \n" ); document.write( "----- \n" ); document.write( "if the volume of gas is inversely proportional to the pressure on the gas, then if we let V = volume, P = pressure, and K = constant of proportionality, we have: \n" ); document.write( "V = K/P \n" ); document.write( "----- \n" ); document.write( "if V = 6 cubic centimeters when the pressure on the gas is 8 kilograms per square centimeter, then the equation becomes: \n" ); document.write( "6 = K/8 \n" ); document.write( "----- \n" ); document.write( "if we solve for K, we get \n" ); document.write( "K = 8*6 = 48 \n" ); document.write( "----- \n" ); document.write( "equation becomes: \n" ); document.write( "6 = 48/8 = 6 which is correct. \n" ); document.write( "the constant of proportionality = K = 48. \n" ); document.write( "----- \n" ); document.write( "your question is: \n" ); document.write( "what is the volume when the pressure is 12 kilograms per square centimeters. \n" ); document.write( "using K = 48, we get: \n" ); document.write( "V = 48/12 = 4 cubic centimeters. \n" ); document.write( "----- \n" ); document.write( "the pressure went from 8 to 12 which means it increased by a factor of 12/8 = 1.5 \n" ); document.write( "since volume and pressure are inversely proportional, you would expect that the volume decreased by the same factor. \n" ); document.write( "6 / 1.5 = 4 \n" ); document.write( "it did. \n" ); document.write( "----- \n" ); document.write( " \n" ); document.write( " |