document.write( "Question 169389: 4x-2/3=>1/3 \n" ); document.write( "

Algebra.Com's Answer #124892 by checkley77(12844) $\"\"$ $\"About$

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4x-2/3=>1/3
\n" ); document.write( "4X>=1/3+2/3
\n" ); document.write( "4X>=1
\n" ); document.write( "X>=1/4 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "LET X=1/3
\n" ); document.write( "4*1/3-2/3>=2/3
\n" ); document.write( "4/3>=2/3+1/3
\n" ); document.write( "4/3>=3/3
\n" ); document.write( "1.333>=1
\n" ); document.write( " \n" ); document.write( "

\n" );