document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169292>Question 169292</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Please help with these two word problems. I just found out from the team leader that she did not post all of our assignments and these two are due tonight from me. I would greatly appreciate your help. <BR>\n" );
document.write( "#94. Golden painting. An artist wants her painting to be in the<BR>\n" );
document.write( "shape of a golden rectangle. If the length of the painting is<BR>\n" );
document.write( "36 inches, then what should be the width? See the previous<BR>\n" );
document.write( "exercise    ***This is the previous exercise:Golden Rectangle. One principle used by the ancient Greeks to get shapes that are pleasing to the eye in art<BR>\n" );
document.write( "and architecture was the Golden Rectangle. If a square<BR>\n" );
document.write( "is removed from one end of a Golden Rectangle, as shown<BR>\n" );
document.write( "in the figure, the sides of the remaining rectangle are<BR>\n" );
document.write( "proportional to the original rectangle. So the length<BR>\n" );
document.write( "and width of the original rectangle satisfy L/W=W/L-W.I hope this is understandable.<BR>\n" );
document.write( "#84. Gone fishing. Debbie traveled by boat 5 miles upstream to<BR>\n" );
document.write( "fish in her favorite spot. Because of the 4-mph current, it<BR>\n" );
document.write( "took her 20 minutes longer to get there than to return. How<BR>\n" );
document.write( "fast will her boat go in still water? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #124887 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=124887\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"cross\" multiplying __ L^2-LW=W^2 __ dividing by W^2 __ (L/W)^2-(L/W)=1\r<BR>\n" );
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document.write( "(L/W)^2-(L/W)-1=0 __ using quadratic formula __ (L/W)=[1ħsqrt(5)]/2\r<BR>\n" );
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document.write( "negative value is not realistic so L/W=[1+sqrt(5)]/2  __ this is the \"Golden Ratio\"\r<BR>\n" );
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document.write( "W=2L/(1+sqrt(5)) __ W=(2*36)/(1+sqrt(5)) __ W=22.25 (approx)\r<BR>\n" );
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document.write( "#84 __ working in miles and hours, so 20min is 1/3 hr __ t=d/r\r<BR>\n" );
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document.write( "let x=\"rate of boat\" __ t=5/(x+4) __ t+(1/3)=5/(x-4)\r<BR>\n" );
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document.write( "substituting __ [5/(x+4)]+(1/3)=5/(x-4)\r<BR>\n" );
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document.write( "multiplying by 3(x+4)(x-4) __ 15x-60+x^2-16=15x+60\r<BR>\n" );
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document.write( "subtracting 15x+60 __ x^2-136=0 __ x=sqrt(136) __ x=11.66 (approx) </SPAN>\n" );
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