document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169385>Question 169385</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Thank you so much nerdybill for helping me with my previous problem, Question 169324. I was raising 1, to the 9th power, which is 1 - instead of 9 to the 1st power.\r<BR>\n" );
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document.write( "I have a second question, I can't seem to wrap my mind around.  How do you solve:\r<BR>\n" );
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document.write( "log base a 5 = 0.699; log base a 3 = 0.477; find log base a 15\r<BR>\n" );
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document.write( "rewritten: log (a,5)=0.699; log (a, 3) = 0.477; find log (a,15). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #124869 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=124869\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  How do you solve: <BR>\n" );
document.write( "log base a 5 = 0.699; log base a 3 = 0.477; find log base a 15 <BR>\n" );
document.write( "rewritten: log (a,5)=0.699; log (a, 3) = 0.477; find log (a,15).<BR>\n" );
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document.write( "The log of a product is the sum of the logs of its elements.<BR>\n" );
document.write( "log(15) = log(3) + log(5), IF they all have the same base.<BR>\n" );
document.write( "So, the log(15) is 0.699 + 0.477<BR>\n" );
document.write( "log(15) = 1.176\r<BR>\n" );
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document.write( " </SPAN>\n" );
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