document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169345>Question 169345</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the distance between (-3,2) and (1,4). Please show work. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #124837 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=124837\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Find the distance between (-3,2) and (1,4). Please show work.<BR>\n" );
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document.write( "Use Pythagoras.  The distance squared is the (diff in x)^2 plus the (diff in y)^2<BR>\n" );
document.write( "s^2 = (x2-x1)^2 + (y2-y1)^2<BR>\n" );
document.write( "s^2 = (1 -(-3))^2 + (4-2)^2<BR>\n" );
document.write( "= (4)^2 + (2)^2<BR>\n" );
document.write( "= 16 + 4<BR>\n" );
document.write( "= 20<BR>\n" );
document.write( "s = sqrt(20) = 2sqrt(5)\r<BR>\n" );
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