document.write( "Question 169338: A pressure of 0.595 atm = ______Torr =_____mmHg. \n" ); document.write( "
Algebra.Com's Answer #124836 by gonzo(654)\"\" \"About 
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your problem:
\n" ); document.write( "A pressure of 0.595 atm = ______Torr =_____mmHg.
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\n" ); document.write( "this website has all the information you need.
\n" ); document.write( "http://en.wikipedia.org/wiki/Torr
\n" ); document.write( "check it out if you have time.
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\n" ); document.write( "from that website:
\n" ); document.write( "1 atm = 760 torr
\n" ); document.write( "1 atm = 101325 Pa
\n" ); document.write( "1 mmHg = 13.5951*9.80665 Pa
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\n" ); document.write( "derived from those formulas in the website:
\n" ); document.write( "1 Pa = (1/101325) atm
\n" ); document.write( "1 Pa = (1/(13.5951*9.80665)) mmHq
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\n" ); document.write( "answer to your question:
\n" ); document.write( ".595 atm = (.595 * 760) torr
\n" ); document.write( ".595 atm = (.595 * 101325) Pa = ((.595*101325) / (13.5951*9.80665)) mmHg
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\n" ); document.write( "numbers come out to be:
\n" ); document.write( ".595 atm = 452.2 torr
\n" ); document.write( ".595 atm = 452.1999356 mmHg
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\n" ); document.write( "1 torr is very close to 1 mmHg as it should be based on the definitions from that website.
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