document.write( "Question 169339: A pressure of 1150 Torr = ______atm.\r
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Algebra.Com's Answer #124832 by gonzo(654)![]() ![]() ![]() You can put this solution on YOUR website! A pressure of 1150 Torr = 1150/760 * atm = 1.513157895 atm. \n" ); document.write( "----- \n" ); document.write( "1 atm = 760 torr \n" ); document.write( "1 torr = 1/760 atm \n" ); document.write( "----- \n" ); document.write( "check this website for more. \n" ); document.write( "http://en.wikipedia.org/wiki/Torr \n" ); document.write( "----- \n" ); document.write( " \n" ); document.write( " |