document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169333>Question 169333</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The denominator of a fraction is 1 more than the numerator. If the numerator is decreased by one and the denominator is increased by 2, the value of the fraction becomes 2/3. Find the fraction. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #124829 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=124829\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The denominator of a fraction is 1 more than the numerator. If the numerator is decreased by one and the denominator is increased by 2, the value of the fraction becomes 2/3. Find the fraction.<BR>\n" );
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document.write( "Let the numerator be \"x\"; then the denominator is \"x+1\".<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "(x+1)/(x+3) = 2/3\r<BR>\n" );
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document.write( "3(x+1) = 2(x+3)<BR>\n" );
document.write( "3x+3 = 2x+6<BR>\n" );
document.write( "x = 3<BR>\n" );
document.write( "x+1 = 4<BR>\n" );
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document.write( "Ans: 3/4<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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