document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169285>Question 169285</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Any help with this problem would be great...<BR>\n" );
document.write( "What rate of interest, to the nearest tenth of a percent, compounded annually is needed for an investment of $1,500 to grow to $3,300 in four years?<BR>\n" );
document.write( "Thanks to all the tutors out there. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #124816 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=124816\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1500(1+r)^4=3300<BR>\n" );
document.write( "(1+r)^4=3300/1500<BR>\n" );
document.write( "(1+r)^4=2.2<BR>\n" );
document.write( "1+r=4thrt(2.2)<BR>\n" );
document.write( "1+r=1.21788<BR>\n" );
document.write( "r=1.21788-1<BR>\n" );
document.write( "r=.21788 ans. for the rate.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "1500(1+.21788)^4=3300<BR>\n" );
document.write( "1500(1.21788)^4=3300<BR>\n" );
document.write( "1500*2.2=3300<BR>\n" );
document.write( "3300=3300 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );