document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169218>Question 169218</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Have trouble understanding sequences, can anyone give assistance?\r<BR>\n" );
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document.write( "Find ratio, r, the general term, a(base-n), and a(base-11)<BR>\n" );
document.write( "2,-6,18,-54,162,... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #124802 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=124802\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> t(n) = a[r^(n-1)]\r<BR>\n" );
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document.write( "where<BR>\n" );
document.write( "t(n) = 'n'th term <BR>\n" );
document.write( "a = first term of the sequence<BR>\n" );
document.write( "r = common ratio between two successive terms\r<BR>\n" );
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document.write( "Here a=2, r=3\r<BR>\n" );
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document.write( "hence you get 2,-6,18,-54,162...<BR>\n" );
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