document.write( "Question 169252: I solved 48 problems but this one has me stumped and I have been working on it for 2hrs.
\n" ); document.write( "Solve the following system of nonlinear equations.
\n" ); document.write( "x^2 + y^2 = 3
\n" ); document.write( "x^2 + y = 0 \n" ); document.write( "
Algebra.Com's Answer #124794 by ankor@dixie-net.com(22740)\"\" \"About 
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Solve the following system of nonlinear equations.
\n" ); document.write( "x^2 + y^2 = 3
\n" ); document.write( "x^2 + y = 0
\n" ); document.write( "---------------Subtraction eliminate x^2
\n" ); document.write( "y^2 - y = 3
\n" ); document.write( ":
\n" ); document.write( "y^2 - y - 3 = 0
\n" ); document.write( ":
\n" ); document.write( "Solve the quadratic equation using the quadratic formula:
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "In this equation a=1, b=-1, c=-3
\n" ); document.write( "\"y+=+%28-%28-1%29+%2B-+sqrt%28-1%5E2+-+4%2A1%2A-3+%29%29%2F%282%2A1%29+\"
\n" ); document.write( ";
\n" ); document.write( "\"y+=+%281+%2B-+sqrt%281+-+%28-12%29+%29%29%2F%282%29+\"
\n" ); document.write( ":
\n" ); document.write( "\"y+=+%281+%2B-+sqrt%2813+%29%29%2F%282%29+\"
\n" ); document.write( "Two solutions
\n" ); document.write( "\"y+=+%281+%2B+3.6%29%2F%282%29+\"
\n" ); document.write( "\"y+=+4.6%2F2\"
\n" ); document.write( "y = 2.3
\n" ); document.write( "and
\n" ); document.write( "\"y+=+%281+-+3.6%29%2F%282%29+\"
\n" ); document.write( "\"y+=+-2.6%2F2\"
\n" ); document.write( "y = -1.3
\n" ); document.write( ":
\n" ); document.write( "Find x using the 2nd equation using y = +2.3
\n" ); document.write( "x^2 + 2.3 = 0
\n" ); document.write( "x^2 = -2.3
\n" ); document.write( "x = Sqrt(-2.3) not a real solution
\n" ); document.write( ":
\n" ); document.write( "Using y = -1.3
\n" ); document.write( "x^2 - 1.3 = 0
\n" ); document.write( "x^2 = +1.3
\n" ); document.write( "x = sqrt(1.3)
\n" ); document.write( "x = 1.14
\n" ); document.write( ":
\n" ); document.write( "Check solution in the 1st equation
\n" ); document.write( "1.14^2 + (-1.3^2) =
\n" ); document.write( "1.3 + 1.69 = 2.99 ~ 3
\n" ); document.write( ":
\n" ); document.write( "Solutions: x = 1.14, y = -1.3
\n" ); document.write( ";
\n" ); document.write( "You can check in the 2nd equation: \n" ); document.write( "
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