document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169202>Question 169202</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A tank contains 440 litres of a mixture which is 23.0% acid. How many litres of a mixture which is 12.0% acid must be added to get a mixture which is 14.5% acid. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #124769 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=124769\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = amount of 12% acid added<BR>\n" );
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document.write( "\"amt of acid from 23%\" + \"amt of acid from 12%\" = \"amt in final mixture\"<BR>\n" );
document.write( ".23(440) + .12x = .145(440+x)<BR>\n" );
document.write( "101.2 + .12x = 63.8 + .145x<BR>\n" );
document.write( "37.4 + .12x = .145x<BR>\n" );
document.write( "37.4 = 0.025x<BR>\n" );
document.write( "1496 liters = x<BR>\n" );
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