document.write( "Question 169141: How do you solve?
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document.write( "x=1/5 y
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document.write( "3x+2y=26 \n" );
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Algebra.Com's Answer #124752 by Alan3354(69443) You can put this solution on YOUR website! How do you solve? \n" ); document.write( "x=1/5 y \n" ); document.write( "3x+2y=26 \n" ); document.write( "-------------- \n" ); document.write( "There are a number of ways, but since x is already shown as a function of y, substitution is probably the simplest. \n" ); document.write( "x=1/5 y \n" ); document.write( "3x+2y=26 \n" ); document.write( "Sub for x in the 2nd eqn \n" ); document.write( "3*(y/5) + 2y = 26 \n" ); document.write( "Multiply by 5 \n" ); document.write( "3y + 10y = 130 \n" ); document.write( "13y = 130 \n" ); document.write( "y = 10 \n" ); document.write( "-------- \n" ); document.write( "x = y/5 \n" ); document.write( "x = 2 \n" ); document.write( "Avoid using 1/5 y, it could mean either (1/5)y or 1/(5y). Use y/5 instead, or add parentheses. Parentheses are free.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |