document.write( "Question 169141: How do you solve?
\n" ); document.write( "x=1/5 y
\n" ); document.write( "3x+2y=26
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Algebra.Com's Answer #124752 by Alan3354(69443)\"\" \"About 
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How do you solve?
\n" ); document.write( "x=1/5 y
\n" ); document.write( "3x+2y=26
\n" ); document.write( "--------------
\n" ); document.write( "There are a number of ways, but since x is already shown as a function of y, substitution is probably the simplest.
\n" ); document.write( "x=1/5 y
\n" ); document.write( "3x+2y=26
\n" ); document.write( "Sub for x in the 2nd eqn
\n" ); document.write( "3*(y/5) + 2y = 26
\n" ); document.write( "Multiply by 5
\n" ); document.write( "3y + 10y = 130
\n" ); document.write( "13y = 130
\n" ); document.write( "y = 10
\n" ); document.write( "--------
\n" ); document.write( "x = y/5
\n" ); document.write( "x = 2
\n" ); document.write( "Avoid using 1/5 y, it could mean either (1/5)y or 1/(5y). Use y/5 instead, or add parentheses. Parentheses are free.\r
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