document.write( "Question 169166: trains a and b are traveling in the same direction on parallel tracks, train a is traveling at 80 miles per hour, and train b is traveling at 100 miles per hour, train a passes a station at 9:10 a.m. if train b passes the same station at 9:25 a.m. at what time will train b catch up to train a. \n" ); document.write( "

Algebra.Com's Answer #124750 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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trains a and b are traveling in the same direction on parallel tracks,
\n" ); document.write( " train a is traveling at 80 miles per hour, and
\n" ); document.write( "train b is traveling at 100 miles per hour,
\n" ); document.write( "train a passes a station at 9:10 a.m.
\n" ); document.write( "if train b passes the same station at 9:25 a.m. at what time will train b catch up to train a.
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\n" ); document.write( "At 9:10, train b is 15 min(.25 hr) from the station
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\n" ); document.write( "At 100 mph that would be .25(100) = 25 mi from the station and from train a
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\n" ); document.write( "The relative speed of the two trains: 100 - 80 = 20 mph
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\n" ); document.write( "How long will it take train b to travel 25 mi at 20 mph
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\n" ); document.write( " $\"25%2F20\"$ = 1.25 hrs or 1 hr 15 min from 9:10 = 10:25 am, train b passes train a
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\n" ); document.write( "We can check that by finding the dist traveled by both trains\r
\n" ); document.write( "\n" ); document.write( "Train a: 1.25(80) = 100 mi
\n" ); document.write( "Train b: 1.25(100) = 125 mi. (It started 25 mi behind train a)
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\n" ); document.write( "Did this make sense? \n" ); document.write( "

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