document.write( "Question 169169: Find the exact value of the expression. sec^-1(-2) \n" ); document.write( "
Algebra.Com's Answer #124747 by jim_thompson5910(35256)\"\" \"About 
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Let \"x=sec%5E%28-1%29%28-2%29\". So this means that \"sec%28x%29=-2\" which further tells \r
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\n" ); document.write( "\n" ); document.write( "\"sec%28x%29=-2\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"1%2Fcos%28x%29=-2\" Replace secant with \"1%2Fcosine\". Take note that cosine is negative (since 1 divided by a negative number is negative). This means that the angle MUST be in either the 2nd or 3rd quadrants.\r
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\n" ); document.write( "\n" ); document.write( "\"1=-2cos%28x%29\" Multiply both sides by \"cos%28x%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"-1%2F2=cos%28x%29\" Divide both sides by -2\r
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\n" ); document.write( "\n" ); document.write( "\"arccos%28-1%2F2%29=x\" Take the arccosine (or inverse cosine) of both sides to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=-pi%2F3\" or \"x=2pi%2F3\" Take the arccosine of \"-1%2F2\" to get \"-pi%2F3\" or \"2pi%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "Since it was stated above that the angle had to be in quadrants 2 or 3, this means that we can ignore \"x=-pi%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "So \"x=2pi%2F3\" which means that \"sec%5E%28-1%29%28-2%29=2pi%2F3\"\r
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