document.write( "Question 169152: Express as a single logarithm:\r
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Algebra.Com's Answer #124736 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"5%2Alog%28e%2C%28x%29%29%2Blog%28e%2C%28y%29%29-2%2Alog%28e%2C%28z%29%29\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"log%28e%2C%28x%5E5%29%29%2Blog%28e%2C%28y%29%29-log%28e%2C%28z%5E2%29%29\" Rewrite the expression using the identity \"y%2Alog%28b%2C%28x%29%29=log%28b%2C%28x%5Ey%29%29\". In other words, place the coefficients as exponents.\r
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\n" ); document.write( "\n" ); document.write( "\"log%28e%2C%28x%5E5y%29%29-log%28e%2C%28z%5E2%29%29\" Combine the first two logs using the identity \"log%28b%2C%28A%29%29%2Blog%28b%2C%28B%29%29=log%28b%2C%28A%2AB%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%28e%2C%28%28x%5E5y%29%2F%28z%5E2%29%29%29\" Combine the logs using the identity \"log%28b%2C%28A%29%29-log%28b%2C%28B%29%29=log%28b%2C%28A%2FB%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "So \"5%2Alog%28e%2C%28x%29%29%2Blog%28e%2C%28y%29%29-2%2Alog%28e%2C%28z%29%29\" simplifies to \"log%28e%2C%28%28x%5E5y%29%2F%28z%5E2%29%29%29\"
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