document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169087>Question 169087</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve log2(x+5) -3 = log2(x-2) ?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #124718 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=124718\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do I solve log2(x+5) -3 = log2(x-2)<BR>\n" );
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document.write( "Subtracting 3 from a log is dividing the antilog by the base to the power of 3, that's the secret.<BR>\n" );
document.write( "log2(x+5) -3 = log2(x-2)<BR>\n" );
document.write( "log2((x+5)/8) = log2(x-2)<BR>\n" );
document.write( "So, (x+5)/8 = x-2<BR>\n" );
document.write( "x+5 = 8x-16<BR>\n" );
document.write( "21 = 7x<BR>\n" );
document.write( "x = 3<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "log2(8) - 3 =? log2(1)<BR>\n" );
document.write( "3-3 = 0, so it's correct.\r<BR>\n" );
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