document.write( "Question 169112: Forty eight more than the second of three consecutive odd integers is the sum of the first and 2/3 of the third. Find the three integers. \n" ); document.write( "

Algebra.Com's Answer #124711 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Forty eight more than the second of three consecutive odd integers is the sum of the first and 2/3 of the third. Find the three integers.
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\n" ); document.write( "The three integers: x, (x+2), (x+4)
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\n" ); document.write( "(x+2) + 48 = x + $\"2%2F3\"$ (x+4)
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\n" ); document.write( "Multiply equation by 3 to get rid of the fraction
\n" ); document.write( "3(x+2) + 3(48) = 3x + 2(x+4)
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\n" ); document.write( "3x + 6 + 144 = 3x + 2x + 8
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\n" ); document.write( "150 - 8 = 3x - 3x + 2x
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\n" ); document.write( "142 = 2x
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\n" ); document.write( "x = 71, the 1st odd integer
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\n" ); document.write( "Check solution in the original equation
\n" ); document.write( "73 + 48 = 71 + $\"2%2F3\"$ 75
\n" ); document.write( "121 = 71 + 50 \n" ); document.write( "

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