document.write( "Question 169108: log5x=log4+log(x+1) \n" ); document.write( "
Algebra.Com's Answer #124708 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! You will need to apply \"log rules\". For a refresher see: \n" ); document.write( "http://www.purplemath.com/modules/logrules.htm \n" ); document.write( ". \n" ); document.write( " log5x=log4+log(x+1) \n" ); document.write( " log5x=log(4(x+1)) \n" ); document.write( " log5x=log(4x+4) \n" ); document.write( " 5x=4x+4 \n" ); document.write( " x=4\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |