document.write( "Question 169108: log5x=log4+log(x+1) \n" ); document.write( "
Algebra.Com's Answer #124708 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
You will need to apply \"log rules\". For a refresher see:
\n" ); document.write( "http://www.purplemath.com/modules/logrules.htm
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\n" ); document.write( " log5x=log4+log(x+1)
\n" ); document.write( " log5x=log(4(x+1))
\n" ); document.write( " log5x=log(4x+4)
\n" ); document.write( " 5x=4x+4
\n" ); document.write( " x=4\r
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