document.write( "Question 169026: b^2+3b+18\r
\n" ); document.write( "\n" ); document.write( "is this prime yes or no?
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Algebra.Com's Answer #124671 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"b%5E2%2B3b%2B18\", we can see that the first coefficient is \"1\", the second coefficient is \"3\", and the last term is \"18\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"1\" by the last term \"18\" to get \"%281%29%2818%29=18\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"18\" (the previous product) and add to the second coefficient \"3\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"18\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"18\":\r
\n" ); document.write( "\n" ); document.write( "1,2,3,6,9,18\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-6,-9,-18\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"18\".\r
\n" ); document.write( "\n" ); document.write( "1*18
\n" ); document.write( "2*9
\n" ); document.write( "3*6
\n" ); document.write( "(-1)*(-18)
\n" ); document.write( "(-2)*(-9)
\n" ); document.write( "(-3)*(-6)\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"3\":\r
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First NumberSecond NumberSum
1181+18=19
292+9=11
363+6=9
-1-18-1+(-18)=-19
-2-9-2+(-9)=-11
-3-6-3+(-6)=-9
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that there are no pairs of numbers which add to \"3\". So \"b%5E2%2B3b%2B18\" cannot be factored.\r
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\n" ); document.write( "\n" ); document.write( "So \"b%5E2%2B3b%2B18\" is prime.
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