document.write( "Question 169035: What is the exact value of this expression. sec^2 50°- tan^2 50° \n" ); document.write( "
Algebra.Com's Answer #124663 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! One of the trigonometric identity is: \n" ); document.write( "1+tan^2 u = sec^2 u \n" ); document.write( ". \n" ); document.write( "Here is a site w/trig identities: \n" ); document.write( "http://www.sosmath.com/trig/Trig5/trig5/trig5.html \n" ); document.write( ". \n" ); document.write( "so, if we started with: \n" ); document.write( "1+tan^2 u = sec^2 u \n" ); document.write( "subtracting tan^2 u from both sides: \n" ); document.write( "1 = sec^2 u - tan^2 u \n" ); document.write( ". \n" ); document.write( "Therefore: \n" ); document.write( "sec^2 50°- tan^2 50° = 1 \n" ); document.write( " |