document.write( "Question 169031: A rectangular parcel of land is 70 ft. longer than it is wide. Each diagonal between opposite corners is 130 ft. What are the dimensions of the parcel? \n" ); document.write( "
Algebra.Com's Answer #124662 by nerdybill(7384)\"\" \"About 
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A rectangular parcel of land is 70 ft. longer than it is wide. Each diagonal between opposite corners is 130 ft. What are the dimensions of the parcel?
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\n" ); document.write( "Let w = width
\n" ); document.write( "then
\n" ); document.write( "w+70 = length
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\n" ); document.write( "Applying Pythagorean theorem:
\n" ); document.write( "w^2 + (w+70)^2 = 130^2
\n" ); document.write( "w^2 + w^2+70w+70w+4900 = 16900
\n" ); document.write( "2w^2 + 140w + 4900 = 16900
\n" ); document.write( "w^2 + 70w + 2450 = 8450
\n" ); document.write( "w^2 + 70w - 6000 = 0
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\n" ); document.write( "Factoring the left:
\n" ); document.write( "(w-50)(w+120) = 0
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\n" ); document.write( "w = {-120, 50}
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\n" ); document.write( "toss out the negative solution:
\n" ); document.write( "width is 50 feet
\n" ); document.write( "length is 50+70= 120 feet\r
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