document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169022>Question 169022</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Natasha drove from Bedington to Portsmouth at an average speed of 100 km/h. On the way back she drove at 75 km/h. Her trip took a total of 3.5 hours. What is the distance between Bedington and Portsmouth? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #124651 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=124651\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Natasha drove from Bedington to Portsmouth at an average speed of 100 km/h. On the way back she drove at 75 km/h. Her trip took a total of 3.5 hours. What is the distance between Bedington and Portsmouth?<BR>\n" );
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document.write( "Let x = time it took do get there<BR>\n" );
document.write( "then<BR>\n" );
document.write( "3.5 - x = time it took to return<BR>\n" );
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document.write( "100x = 75(3.5 - x)<BR>\n" );
document.write( "100x = 262.5 - 75x<BR>\n" );
document.write( "175x = 262.5<BR>\n" );
document.write( "x = 1.5 hours<BR>\n" );
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document.write( "To find distance, we multiply the above by the 100 km/hr to get there:<BR>\n" );
document.write( "1.5 * 100 = 150 km <BR>\n" );
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