document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169022>Question 169022</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Natasha drove from Bedington to Portsmouth at an average speed of 100 km/h. On the way back she drove at 75 km/h. Her trip took a total of 3.5 hours. What is the distance between Bedington and Portsmouth? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #124650 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=124650\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "100X=75(3.5-X)<BR>\n" );
document.write( "100X=262.5-75X<BR>\n" );
document.write( "100X+75X=262.5<BR>\n" );
document.write( "175X=262.5<BR>\n" );
document.write( "X=262.5/175<BR>\n" );
document.write( "X=1.5 HOURS FOR THE 100 KMH DRIVE.<BR>\n" );
document.write( "3.5-1.5=2 HOURS FOR THE 75 KMH DRIVE.<BR>\n" );
document.write( "100*1.5=75*2<BR>\n" );
document.write( "150=150 ANS. FOR THE DISTANCE BETWEEN BEDINGTON & PORTSMOUTH. \r<BR>\n" );
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