document.write( "Question 169002This question is from textbook college algebra
\n" ); document.write( ": can somebody help me solve this equation: \"5%5E%28x%2B2%29=7%5E%28x-2%29\" \n" ); document.write( "
Algebra.Com's Answer #124630 by Electrified_Levi(103)\"\" \"About 
You can put this solution on YOUR website!
Hi, Hope I can help
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\n" ); document.write( "can somebody help me solve this equation: \"5%5E%28x%2B2%29=7%5E%28x-2%29\"
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\n" ); document.write( "first we must take the log of both sides, log is the inverse function of an exponent, it is also the power of a base function
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\n" ); document.write( "The two sides will have a base of \"10\"
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\n" ); document.write( " \"log+%2810%2C+5%5E%28x%2B2%29%29=log+%28+10%2C7%5E%28x-2%29%29\"
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\n" ); document.write( "\"+log+%28+a%2C+b%5Ec+%29+=+%28c%29%28log%28a%2Cb%29%29+\", if there is an exponent in a log such as (x+2), and (x-2), you take the exponents and multiply them by (
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\n" ); document.write( "\"+log+%2810%2C+base%29+\"), in this case \"+log+%28+10%2C5%29\", and \"+log+%2810%2C7%29+\"
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\n" ); document.write( "\"%28x%2B2%29log+%2810%2C5%29=%28x-2%29log+%28+10%2C7%29\",
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\n" ); document.write( "We can rearrange the two sides
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\n" ); document.write( "\"%28x%2B2%29log+%2810%2C5%29=%28x-2%29log+%28+10%2C7%29\" = \"log+%2810%2C5%29%28x%2B2%29=log+%28+10%2C7%29%28x-2%29\"
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\n" ); document.write( "we can use the distribution to multiply the numbers out
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\n" ); document.write( "\"log+%2810%2C5%29%28x%2B2%29=log+%28+10%2C7%29%28x-2%29\" = =
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\n" ); document.write( "Remember the signs
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\n" ); document.write( " now we need to get all the \"x\"s on one side, we will move \"+x%28log+%28+10%2C7%29%29+\", to the left side
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\n" ); document.write( "Now we will move \"+2log+%2810%2C5%29+\" to the right side
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\n" ); document.write( "We can take out the \"x\"s on the left side ( since they both have it in common
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\n" ); document.write( " = \"+x%28log+%28+10%2C5+%29+-+log+%28+10%2C7%29%29+=+-+2log+%28+10%2C7%29+-+2log+%2810%2C5%29+\"
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\n" ); document.write( "To find \"x\" you would divide both sides by \"+log+%28+10%2C5+%29+-+log+%28+10%2C7%29+\"
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\n" ); document.write( "\"+x%28log+%28+10%2C5+%29+-+log+%28+10%2C7%29%29+=+-+2log+%28+10%2C7%29+-+2log+%2810%2C5%29+\" = =
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\n" ); document.write( " = \"+x+=+21.13308+\" (rounded)(you have to solve using a calculator)
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\n" ); document.write( "You usually check by replacing \"x\" with the answer, but in this case, it would be hard since the answer never stops ( I checked it, and it is right )
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\n" ); document.write( "Hope I helped, Levi
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