document.write( "Question 2690: Question: F'ind the equation of the line that passes through the point (6,2) and is perpendicular to the line y=(-1/3)x + 6
\n" ); document.write( "Write the equation of the line in standard form with integral coefficients
\n" ); document.write( "I know ax + by = c
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Algebra.Com's Answer #1246 by xcentaur(357)\"\" \"About 
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Given:
\n" ); document.write( "P=(6,2)
\n" ); document.write( "y=(-1/3)x+6 ..... [line 1]
\n" ); document.write( "[Line 2](eqn unknown) is perpendicular to [Line 1]
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\n" ); document.write( "We know that if two lines are perpendicular,the product of their slopes is -1.
\n" ); document.write( "ie. m1*m2=-1
\n" ); document.write( "Let slope of line 1 be m1.
\n" ); document.write( "Then,
\n" ); document.write( "-1/3*m2=-1
\n" ); document.write( "m2=(-1*3)/-1
\n" ); document.write( " =3
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\n" ); document.write( "Then slope of required line is 3.
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\n" ); document.write( "We have one point P(6,2) on this line of slope 3.
\n" ); document.write( "Then using point-slope form,\r
\n" ); document.write( "\n" ); document.write( "y-y1=m(x-x1)
\n" ); document.write( "y-2=3(x-6)
\n" ); document.write( "y-2=3x-18
\n" ); document.write( "y=3x-18+2
\n" ); document.write( "y=3x-16
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\n" ); document.write( "Equation of the line in standard form: y = 3x - 16
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\n" ); document.write( "Hope this helps,
\n" ); document.write( "best of luck. \n" ); document.write( "

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